a^2-11a+8=0

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Solution for a^2-11a+8=0 equation: 



a^2-11a+8=0

a = 1; b = -11; c = +8;
Δ = b2-4ac
Δ = -112-4·1·8
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{89}}{2*1}=\frac{11-\sqrt{89}}{2}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{89}}{2*1}=\frac{11+\sqrt{89}}{2}
$

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